I'm a new bee in arm assembly language.I objdump a simple program, and the following is the assembly code of main function:
00010438 <main>:
10438: e92d4800 push {fp, lr}
1043c: e28db004 add fp, sp, #4
10440: e24dd010 sub sp, sp, #16
10444: e59f3068 ldr r3, [pc, #104] ; 104b4 <main+0x7c> <--(QUESTION：0x10444+104≠0x104b4, why?)
10448: e50b300c str r3, [fp, #-12]
1044c: e59f3064 ldr r3, [pc, #100] ; 104b8 <main+0x80>
10450: e50b3010 str r3, [fp, #-16]
10454: e59f3060 ldr r3, [pc, #96] ; 104bc <main+0x84>
10458: e5933000 ldr r3, [r3]
1045c: e50b3014 str r3, [fp, #-20] ; 0xffffffec
10460: e3a03000 mov r3, #0
10464: e50b3008 str r3, [fp, #-8]
10468: ea000008 b 10490 <main+0x58>
1046c: e51b3008 ldr r3, [fp, #-8]
10470: e2832001 add r2, r3, #1
10474: e50b2008 str r2, [fp, #-8]
10478: e24b2004 sub r2, fp, #4
1047c: e0823003 add r3, r2, r3
10480: e5533010 ldrb r3, [r3, #-16]
10484: e1a01003 mov r1, r3
10488: e59f0030 ldr r0, [pc, #48] ; 104c0 <main+0x88>
1048c: ebffff9e bl 1030c <printf@plt>
10490: e51b3008 ldr r3, [fp, #-8]
10494: e3530003 cmp r3, #3
10498: dafffff3 ble 1046c <main+0x34>
1049c: e3a0000a mov r0, #10
104a0: ebffffa2 bl 10330 <putchar@plt>
104a4: e3a03000 mov r3, #0
104a8: e1a00003 mov r0, r3
104ac: e24bd004 sub sp, fp, #4
104b0: e8bd8800 pop {fp, pc}
104b4: 00000539 .word 0x00000539
104b8: 00010534 .word 0x00010534
104bc: 00010548 .word 0x00010548
104c0: 00010540 .word 0x00010540
My question is on line 5 of the code above.Thanks.
