remove _id from the return of MongoDB

Question

I have this.

app.get('/messages/all', async function (req, res) { 
const messages = await collection.find({}).toArray(); 
res.send(messages)

And i do this.

curl -X GET http://localhost:3000/messages/all

And this return this.

[{"_id":"5e973b8669e20600a59cd2b2","from":"user","msg":"ville"},{"_id":"5e973b8669e20600a59cd2b3","from":"bot","msg":"Nous sommes à Paris"}]

But i don't want the id. So i want to remove the _id.

Can i have help (i am not english and 19 dont judge me pls)

Does this answer your question? [remove \_id from mongo result](https://stackoverflow.com/questions/9601219/remove-id-from-mongo-result) — whoami - fakeFaceTrueSoul, Apr 15 '20 at 19:47

score 2 · Answer 1 · answered Apr 15 '20 at 18:13

2

If collection.find({}) is a mongo call, then you can exclude the _id.

collection.find({}, {_id: 0})

The second argument to the find is the projection.

answered Apr 15 '20 at 18:13

Taplar

score 2 · Answer 2 · answered Nov 25 '22 at 10:34

2

With nodejs and recent mongodb client (tested using 4.7.0), the syntax is:

collection.find({}, { projection: { _id: false } })

answered Nov 25 '22 at 10:34

mrtnlrsn

Mohammad Ali Rony · Answer 3 · 2020-04-15T18:17:27.593

1

You can add false like {"_id": false} MongoDB not to return _id from the collection

collection.find({},{"_id" : false}).toArray()

or you can use delete _id property from object javascript array

messages.forEach(function(v){ delete v._id});

edited Apr 15 '20 at 18:17

answered Apr 15 '20 at 18:12

Mohammad Ali Rony

score 0 · Answer 4 · answered Apr 15 '20 at 18:11

In JavaScript, use the delete operator to remove a prop from an object:

let messages = collection.find({}).toArray()
messages = messages.map((doc) => {
  delete doc._id
  return doc
})

4 Answers4