Assigning itself values in post increment and in pre increment

Question

I'm new to the coding can anyone explain to me why below code is giving output as '6'

class Test{
    public static void main(String[] args) {
        int i = 5;
        i = i++;
        i = ++i;
        System.out.print(i);
    }
}

The middle statement is effectively a no-op. `i = i++;` does not change `i`. — Elliott Frisch, Dec 06 '18 at 16:53

score 1 · Answer 1 · answered Dec 06 '18 at 16:53

1

i = i++; This line assign 5 to i again you can run this code to ensure about that:

class Test{
    public static void main(String[] args) {
        int i = 5;
        i = i++;
        System.out.println(i);
        i = ++i;
        System.out.println(i);
    }
}

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answered Dec 06 '18 at 16:53

Mohsen

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why this line "i = i++; This line assign 5 to i " ? can you explain? – user3359125 Dec 06 '18 at 17:24
@user3359125 this is what post increment do for us. It first assign current value of `i` to itself then increment it by one – Mohsen Dec 06 '18 at 17:26

Assigning itself values in post increment and in pre increment

1 Answers1