Python program assigning code to random integer, and checking with user input not functioning

Question

#test
import subprocess
import time
import random
programClass=[]
code=random.randint(100,1000)
print('This is your secret code! PLEASE WRITE THIS DOWN!')
print(code)
numRafflePeople=0

tester=1
while tester==1:
    code1=input('What is your name, phone number, and email?\n')
    print('code',code1)
    code=code
    if code==code1:
        print('Blah')
        time.sleep(5)
        tester=2
    else:
        print('fail')
        tester=1

This program makes a random number, then checks to see if the inputed number is the same as the random number, however when I run the program the program does not seem to be able to identify they are the same.

The random number will be like 303. I will type 303, and the fail message will be printed, can someone please explain the error in my code?

Please try to create a [mcve]. The while loop is not necessary for the issue here — OneCricketeer, Nov 30 '17 at 03:57
Possible duplicate of [How can I read inputs as integers?](https://stackoverflow.com/questions/20449427/how-can-i-read-inputs-as-integers) — OneCricketeer, Nov 30 '17 at 03:58
Its fine, I got the answer I desired, the while loop is necessary for my bigger project, but it seemed to big — QuestionedE, Nov 30 '17 at 03:59
My point is that you should post a smaller example that reproduces the issue. Basically, you're comparing a string to an int — OneCricketeer, Nov 30 '17 at 04:00
Thats what I'm trying to do in this certain example, thanks though ill remember this for the future! You have been a great help towards asking relevant questions! — QuestionedE, Nov 30 '17 at 04:02

score 3 · Accepted Answer · edited Nov 30 '17 at 04:01

3

When the user gives input, code1 becomes a string. code is an integer.

When comparing the two in the boolean, code==code1, it will always be false.

Just change it to:

code1=int(input('What is your name, phone number, and email?\n'))

edited Nov 30 '17 at 04:01

OneCricketeer

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answered Nov 30 '17 at 04:00

Kevin Penkowski

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2

Reblochon Masque · Answer 2 · 2017-11-30T03:56:41.743

1

You must convert your input to int:

import time
import random

code = random.randint(100,1000)
print('This is your secret code! PLEASE WRITE THIS DOWN!')
print(code)

tester = 1
while tester == 1:
    code1 = int(input('What is your name, phone number, and email?\n'))
    print('code', code1)
    if code == code1:
        print('Blah')
        time.sleep(5)
        tester = 2
    else:
        print('fail')
        tester = 1

edited Nov 30 '17 at 03:56

answered Nov 30 '17 at 03:53

Reblochon Masque

35,405
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Thanks! I was hoping I could accept both `str` and `int` inputs, is that possible? – QuestionedE Nov 30 '17 at 03:58
@Ques `input()` **always** returns a `str` in Python3 – OneCricketeer Nov 30 '17 at 03:59
Though in this circumstance can I accept both `str` and `int` inputs throughout the same `input('___')` question? – QuestionedE Nov 30 '17 at 04:00
As @cricket_007 said. You always retrieve a string with user input; depending on your use case, you may have to cast it, or parse it. – Reblochon Masque Nov 30 '17 at 04:01

Python program assigning code to random integer, and checking with user input not functioning

2 Answers2