Swift: Show success screen after login

Question

Here is my code:

if(statusCode != 200) {

                let jsonStr = NSString(data: data!, encoding: NSUTF8StringEncoding)
                print("Error could not parse JSON: '\(jsonStr)'")
            }
            else {

                print("Everything Looks good: \(responseData)")
                self.performSegueWithIdentifier("login", sender: self)

            }

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
        super.prepareForSegue(segue, sender: sender)
    }

performSegueWithIdentifier does not do anything.

Update

print("Everything Looks good: \(responseData)")
                dispatch_async(dispatch_get_main_queue(),{
                    self.performSegueWithIdentifier("logi‌n", sender: self)
                })

throws

2015-07-16 00:40:18.298 phoenix[2750:259334] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Receiver (<phoenix.LoginViewController: 0x7fab62514d30>) has no segue with identifier 'logi‌n''
*** First throw call stack:

It should not be the case, because enter image description here

Try this, `dispatch_async(dispatch_get_main_queue(),{self.performSegueWithIdentifier("login", sender: self)})` — Akhilrajtr, Jul 16 '15 at 04:33
If it logs `Everything Looks good ..` then make sure the segue name is correct. — Akhilrajtr, Jul 16 '15 at 04:38
where have you coded success controller's name ? it is showing `login` — iRiziya, Jul 16 '15 at 04:41
Shouldn't be there something like `self.performSegueWithIdentifier("success", sender: SuccessViewController.self)` ?? — iRiziya, Jul 16 '15 at 04:43
can we take a look at the ID of ViewController in storyboard? — Siu Chung Chan, Jul 16 '15 at 04:46
Try [cleaning](http://stackoverflow.com/questions/5714372/how-to-empty-caches-and-clean-all-targets-xcode-4/6247073#6247073) the cache and build then check again. — Akhilrajtr, Jul 16 '15 at 04:57

Swift: Show success screen after login

0 Answers0