Assigning objects in a loop

Question

My question is very simple I searched it and thought that I found the solution but I get an error. Here's my problem:

I have some files like this:

Mor_ldnew1.txt
Mor_ldnew2.txt
Mor_ldnew3.txt
.
.
.

And I want to store each of this files in different objects to then merge them but I got an error with my loop:

    for (i in 1:3){

read.table(paste("Mor_ld_new",i,".txt", sep="")) -> mor[i]      
}

This is the error:

Error: unexpected '}' in "        }"

Thanks in advance.

What kind of syntax is `mor([i])`? Also, use `lapply`. There are many answers on SO, which show how to import files from a directory using `lapply`, e.g. [here](http://stackoverflow.com/a/9565095/1412059). — Roland, Feb 05 '14 at 16:22

score 2 · Answer 1 · answered Feb 05 '14 at 16:22

2

You need to remove the parentheses around the [i].

A more idiomatic way to write it would to use lapply.

answered Feb 05 '14 at 16:22

I tried it but still nothing. – JM88 Feb 05 '14 at 16:32
Error in mor[i] <- read.table(paste("MorN_LD_new", i, ".txt", sep = "")) : object 'mor' not found – JM88 Feb 05 '14 at 16:34
You have to define `mor` first. Make sure you preallocate the list first (`mor <- vector('list', length = n.files)`) – Christopher Louden Feb 05 '14 at 16:42
I used mor <- vector('list', length=10) and the run the loop. No error but there are no objects named mor1, mor2, ... – JM88 Feb 05 '14 at 16:50
The data is all stored in `mor`. You can access the ith one by `mor[[i]]`. – Christopher Louden Feb 05 '14 at 16:51
I will take a look, but isn't there a way to have mor1, mor2, mor3, mor4, mor5, in different objects so I can merge them later? – JM88 Feb 05 '14 at 16:55
I am googling lapply for naming objects in google but no luck either. – JM88 Feb 05 '14 at 16:55
You can apply merge on a list assuming they have a common key using `lapply`. – Christopher Louden Feb 05 '14 at 16:56

score 0 · Answer 2 · answered Feb 05 '14 at 17:56

0

Using the loop:

for (i in 1:3){
assign(paste0("mor", i), read.table(paste("Mor_ld_new",i,".txt", sep="")))
}

answered Feb 05 '14 at 17:56

Carlos Cinelli

2 Answers2